 # Competitive Exam Notes for Percentage (प्रतिशत)

### प्रतिशत का अर्थ होता है  ‘प्रत्येक सो ‘

“प्रतिशत  एक  भिन्न  होता है जिसका हर 100 है और भिन्न के अंश को रेट प्रतिशत कहा जाता है”| प्रतिशत को  % प्रतीक द्वारा लिखा जाता है|

प्रतिशत की गणना करने का कांसेप्ट

यदि हमें x का y% ज्ञात करना है तो,
x का y% =(x*y)/100

प्रतिशत का भिन्न में परिवर्तन

Expression per cent (x%) into fraction.
Required fraction=x/100

भिन्न का प्रतिशत में परिवर्तन

Expressing a fraction (x/y) in per cent.
Required percentage=(x/y)*100)%

अन्य के सम्बन्ध में एक मात्रा की प्रतिशत के रूप में अभिव्यक्ति

To express a quantity as a per cent with respect to other quantity following formula is used.
(The quantity to be expressed in per cent)/ (2nd quantity (in respect of which the per cent has to be obtained))X100%

महत्वपूर्ण कांसेप्ट और ट्रिक

1. If x% of A is equal to y% of B, then
z% of A=(yz/x)% of B

2. When a number x is increased or decreased by y%, then the new number will be
(100+y)*x/100

3. When the value of an object is first changed (increased ) by a% and then changed (increased ) by b%,then
Net effect=[a+b +ab/100]%

4. Suppose in an examination, x% of total number of students failed in subject A and y% of total number of students failed in subject B and z% failed
in both the suject. Then,
(i) Percentage of students who passed in both the subjects=[100-(x+y-z)]%
(ii) Percentage of students who failed in either subject=(x+y-z)%

5. If due to r% decrease in the price of an item, a person can buy A kg more in Rs.x, then
Actual price of that item= Rs (rx)/((100-r)A) Per kg

Example :If due to 10% increase in the price of sugar ,Ram can buy 5 kg more sugar in Rs 100 , then find the actual Price of sugar ?

solution : Here r = 10 % ,x = 100 and A = 5 kg
Actual price of sugar = 10*100/((100-10 )*5) =  Rs. 2(2/9)

6.If the population of a town is P and it increases at the rate of R% per annum, then
(i) Population after n yr= P(1+r/100)^n
(ii) Population, n yr ago=P/(1+r/100)^n

7. If the present population of a city is P and there is a increment  of R1%, R2% ,R3% in first, second and third year respectively, then

Population of city after 3 yr=P(1+R1/100)(1+R2/100)(1+R3/100)

Example : Population of a city in 20004 was 1000000. If in 2005 there is an increment of 15 % , in 2006 there is a decrement of 35 % and in 2007 there is an increment of 45 %, then find the population of city at the end of the year 2007.

solution : Required population = P (1 + R1/100)(1 – R2/100)(1 + R3/100)

P (1 + 15/100)(1 – 35/100)(1 + 45/100)
= 1083875