 # Problems on Calendar: Basic Concept, Solved Examples and Questions

Hello to all, I hope you would have liked my last article on clock and have solved all the questions easily. But if you are finding it difficult to solve then you can tell your doubts in the comment section below. Today I’m going to discuss a very important topic that is ‘Calendar’. In this article I will tell what is the basic concept of Calendar, Solved Examples on Calendar and then 4-5 questions that you have to solve it on your own. Don’t worry would not be that difficult that you cannot solve. So let us start with today’s topic that is Calendar.

# Basic Concept:-

Here we are supposed to find the day of the week on a given date. For this we use the concept of odd days.

Odd days: In a given period, the number of days more than the complete weeks are called odd days.

Leap Year: Every year divisible by 4 is leap year, if it is not a century. Every 4th century is a leap year, if it is not a century. Every 4th century is leap year and no other century is a leap year.

Eg: Each of the year 1948,2004,1674 etc is a leap year.

And none of the years 2001,2002,2003,2005 etc is not a leap year.

Ordinary Year: The year which is not a leap year is called as leap year. And it has 365 days. whereas a leap year has 366 days.

Counting on odd days:

(i) 1 ordinary year = 365 days = (52 weeks + 1 day)

Therefore 1 ordinary year has 1 odd day.

(ii) 1 leap year = 366 days = (52 weeks + 2 days)

Therefore 1 leap year has 2 odd days.

# Solved Examples:

Ex: What was the day of the week on 16th July, 1776?

Solution: 16th July 1776 = (1775 years + period from 1.1.1776 to 16.7.1776)

Counting on odd days:

Number of odd days in 1600 years = 0

Number of odd days in 100 years = 5

75 years = 18 leap years + 57 ordinary years

= (18 * 2 + 57 * 1) odd days = 93 odd days

= (13 weeks + 2 days) = 2 odd days

Therefore 1775 years have

= (0 + 5 + 2) odd days = 7 odd days = 0 odd day

Jan.               Feb            Mar           Apr      May        June        July

(31       +        29      +       31        +    30   +   31      +     30      +    16) = 198 days

198 days = ( 28 weeks + 2 days) = 2 odd days

Therefore Total number of odd days = (0 + 2) = 2.

Hence the required day is Tuesday.

Ex: What was the day of the week on 15th August, 1947?

Solution:

15th August 1947 = (1946 years + period from 1.1.1947 to 15.8.1947)

Counting on odd days:

Number of odd days in 1600 years = 0

Number of odd days in 300 years = 15 is equivalent to 1

46 years = 11 leap years + 35 ordinary years

= (11 * 2 + 35 * 1) odd days = 57 odd days

= (8 weeks + 1 day) = 1 odd day

Therefore 1946 years have

= (0 + 1 + 1) = 2

Jan.               Feb            Mar           Apr      May        June        July       Aug

(31       +        29      +       31        +    30   +   31      +     30      +    31    +   15) = 227 days

227 days = ( 32 weeks + 3 days) = 3 odd days

Therefore Total number of odd days = (3 + 2) = 5.

Hence the required day is Friday.

# Homework Questions:

1. Jan. 1, 2008 is Tuesday. What day of week lies on Jan 1,2009?

a. Monday        b. Wednesday        c. Thursday        d. Sunday

2. On 6th March, 2005 Monday falls. What day of the week was it on 6th March 2004?

a. Sunday      b. Saturday      c. Tuesday       d. Wednesday

3. What day of the week on 17th June, 1998?

a. Monday       b. Tuesday       c. Wednesday     d. Thursday

4. For a certain month, the dates of three of the Sundays are Even Numbers. Then the 15th of that month falls on a (SSC-CGL TIER 1 EXAM, 2012)

a.Thursday       b. Friday        c. Saturday      d. Sunday

I hope you have understand the concept of calendar and now please solve the homework questions to check your understanding. For more notes and articles please subscribe to http://banking.eckovation.com/ Share with your friends also. For more information please visit to https://www.eckovation.com/ and do join the group. It will definitely help you. Thank you. All the best.