Problems on Time and Work : Quantitative Aptitude
So, you are well prepared for the exam and have decided how much time you allot to every question for the best outcome of the exam. I am not going to discuss that point but the “Time And Work” problems asked in the eams.
Work is any action performed which takes some input and produces some output accordingly.
Basic formulae and tricks
 More men can do more work
 More men can do same work in less time
 More work means more time required.
 More efficient men can do work quickly.
 If x men can finish a work in t days then
total work done = x*t

If A can do a piece of work in n days, work done by A in 1 day = 1/n

If A does 1/n work in a day, A can finish the work in n days

If M1 men can do W1 work in D1 days working H1 hours per day and M2 men can do W2 work in D2 days working H2 hours per day (where all men work at the same rate), then
(M1 D1 H1) / W1 = (M2 D2 H2) / W2

If A can do a piece of work in p days and B can do the same in q days,
A and B together can finish it in pq / (p+q) days
5. If A is thrice as good as B in work, then
The ratio of work done by A and B = 3: 1
The ratio of time taken to finish a work by A and B = 1 : 3
Here are some questions for your practice
Q1. P, Q, and R can completely solve a problem together in 4 hrs. P and R together take 15 hrs less than Q working alone. Q works on the problem for first 2 hrs and then P and R joins him. After another two hours, Q quits. In how many hours is the problem actually solved?
Sol. Let Q alone can answer the problem in x hours
Then P&R together needs (x15) hours to solve the problem
In 1 hr, Q can complete 1/x of the question,
In 1 hr, P&R can complete 1/(x15) of the question
In 1 hr, P, Q, and R can complete 1/4th of the question
1/x + 1/(x15) = 1/4
4(x15)+4x =x(x15)
4x – 60 + 4x = x^2 – 15x
x^2 – 23x + 60 = 0
(x20)(x3)=0
x = 20 or 3
since (x15) is positive, x = 20
In 1 hr, Q can complete 1/20 of the question.
In 1 hr, P and R can complete 1/5 of the question
In 1 hr, P, Q, and R can complete 1/4 of the question
In the first two hours, 2* 1/20 = 1/10 of the question is completed by Q
P, Q, and R work in next 2 hrs and completes 2 * 1/4 = 1/2 of the question
Remaining part = 1 – 1/10 – 1/2 = 2/5
Let P&R work for n hours and completes this part
n = (2/5)/(1/5) = 2
Total time taken to solve the question = 2+2+2 = 6 hours
Q.2 A is twice as good a workman as B and is, therefore, able to finish a piece of work in 30 days less than B.In how many days they can complete the whole work; working together?
Sol.
The ratio of times taken by A and B = 1: 2.
The time difference is (2 – 1) 1 day while B takes 2 days and A takes 1 day.
If the difference of time is 1 day, B takes 2 days.
If the difference of time is 30 days, B takes 2 x 30 = 60 days.
So, A takes 30 days to do the work.
A’s 1 day’s work = 1/30
B’s 1 day’s work = 1/60
(A + B)’s 1 day’s work = 1/30 + 1/60 = 1/20
A and B together can do the work in 20 days.
Q.3 A can do a certain work in the same time in which B and C together can do it. If A and B together could do it in 20 days and C alone in 60 days, then B alone could do it in
Sol.
(A+B)’s 1 day’s work=1/20
C’s 1 day work=1/60
(A+B+C)’s 1 day’s work= 1/20 + 1/60 = 1/15
Also A’s 1 day’s work =(B+C)’s 1 day’s work
Therefore, we get: 2 x (A’s 1 day ‘s work)=1/15
=>A’s 1 day’s work=1/30
Therefore, B’s 1 day’s work= 1/20 – 1/30 = 1/60
So, B alone could do the work in 60 days
Q4. 12 men can complete a work in 8 days. 16 women can complete the same work in 12 days. 8 men and 8 women started working and worked for 6 days. How many more men are to be added to complete the remaining work in 1 day?
Sol. 1 man’s 1 day work =1/96 ; 1 woman’s 1 day work = 1/192
Work done in 6 days=6(896+8192)=6×18 =346896+8192=6×18 =34
Remaining work = 1/4
(8 men +8 women)’s 1 day work = 1(896+8192)1896+8192 =1/8
Remaining work =1/4 – 1/8 = 1/8
1/96 work is done in 1 day by 1 man
Therefore, 1/8 work will be done in 1 day by 96 x (1/8) =12 men
I think now you have got basic ideas about the questions , below I am providing you with some questions for practice.
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